Given
The temperatures are;
[tex]\begin{gathered} T_1=0^oC \\ T_2=100^oC \end{gathered}[/tex]
The area of the rectangular bar
[tex]A=2.25cm\times2.25cm=5.06\times10^{-4}m[/tex]
The length of the rectangular bar is
[tex]l=0.500\text{ m}[/tex]
The rate of heat transferr is
[tex]\frac{Q}{t}=15\text{ J/s}[/tex]
To find
The thermal conductivity of the bar
Explanation:
The rate of heat transfer is:
[tex]\begin{gathered} \frac{Q}{t}=kA\frac{T_2-T_1}{l} \\ \Rightarrow15=k\times5.06\times10^{-4}\times\frac{100-0}{0.5} \\ \Rightarrow k=148.221W/m^oC \end{gathered}[/tex]
Conclusion
The thernal conductivity is
[tex]148.221W/m^oC[/tex]