We are given that the graph of the function passes through (-4,19), and (7,3), therefore:
[tex]\begin{gathered} 19=ab^{-4}, \\ 3=ab^7. \end{gathered}[/tex]Dividing the second equation by the first one, we get:
[tex]\begin{gathered} \frac{3}{19}=\frac{ab^7}{ab^{-4}}=\frac{3}{19}=b^{7+4}, \\ b^{11}=\frac{3}{19}, \\ b=\sqrt[11]{\frac{3}{19}}. \end{gathered}[/tex]Now, substituting the above result in the second equation, we get:
[tex]\begin{gathered} a(\sqrt[11]{\frac{3}{19}})=3, \\ a=\frac{3}{(\sqrt[11]{\frac{3}{19}})^7}. \end{gathered}[/tex]Rounding b to 4 decimal places, we get:
[tex]\begin{gathered} \\ b\approx0.8455. \end{gathered}[/tex]