Given:
[tex]\frac{7x -3}{9}\ge8-2x[/tex]
On simplification we get,
[tex]\begin{gathered} \frac{7x -3}{9}\ge8-2x \\ 7x-3\ge72-18x \\ 7x+18x\ge72+3 \\ 25x\ge72 \\ x\ge3 \end{gathered}[/tex]
Since, the value of x is greater than or equal to 3.
Hence, the correct option is C.
