ANSWER
[tex]10^{12}[/tex]EXPLANATION
We want to find out how many times 3.8 x 10^5 is greater than 3.8 x 10^-7.
To do that, we have to divide 3.8 x 10^5 by 3.8 x 10^-7 and then find the answer.
Let us do that:
[tex]\begin{gathered} \frac{3.8\cdot10^5}{3.8\cdot10^{-7}}\text{ = }\frac{3.8}{3.8}\cdot\text{ }\frac{10^5}{10^{-7}} \\ U\sin g\text{ the division law of indices:} \\ 1\cdot(10^{5\text{ -(-7)}})=10^{5+7} \\ =10^{12} \end{gathered}[/tex]Note: The division law of indices states that if a numerator and a denominator have the same base (e.g. 10), then the power of the numerator can subtract of the denominator.
Therefore, 3.8 x 10^5 is greater than 3.8 x 10^-7 by 10^(12) times
