TrishT522409 TrishT522409

30-10-2022
Physics

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Gold is sold by the troy ounce (31.103 g). What is the volume (in cm3) of 5 troy ounces of pure gold?

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JhonaelV706015 JhonaelV706015

30-10-2022

Answer:

Volume = 8.05 cm³

Explanation:

The mass of 1 troy of gold, m = 31.103 g

Mass of 5 trounce = 5 x 31.103 = 155.515 g

Density of gold, ρ = 19.320 g/cm³

Density = Mass/Volume

Volume = Mass/Density

Volume = 155.515/19.320

Volume = 8.05 cm³

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