Question

I need help on this please

Answer 1

$\frac{1}{9}$

Explanation

$a^{-2}b^0$

let's remember some properties of the exponents numbers

$\begin{gathered} a^{-n}=\frac{1}{a^n} \\ a^0=1\text{ ( any number to the zero exponent equals 1)} \end{gathered}$

then,

solve by appling the properties

for a= -3 and b=-3

replace.

$\begin{gathered} a^{-2}b^0 \\ (-3^{-2})(-3^0) \\ (\frac{1}{(-3)^2})(1) \\ (\frac{1}{3\cdot3})(1) \\ (\frac{1}{9})(1) \\ \frac{1}{9} \end{gathered}$

so, the answer is

$\frac{1}{9}$

I hope this helps you