Question

Solve u^2= -36 where U is a real number.Simplify you answer as much as possible.If there are more than one solution separate them with commas.If there no solution just put that as the answer u=

Answer 1

Step 1

Given;

$u^2=-36$

Required; To find the value of u

Step 2

Find the value of u

$\begin{gathered} Take\text{ the square root of both sides} \\ \sqrt{u^2}=\sqrt{-36} \\ u=\pm(\sqrt{-1}\times\sqrt{36})\text{ but }\sqrt{-1}=i \\ u=\pm6i \end{gathered}$

+6i and -6i are not real numbers. Therefore the answer will be;

$No\text{ solution}$