to find the inverse function...
[tex]y=9x^2-12[/tex]change y for x and x for y
[tex]x=9y^2-12[/tex]and solve y
[tex]\begin{gathered} 9y^2=x+12 \\ y^2=\frac{x+12}{9} \\ \\ y=\sqrt[]{\frac{x+12}{9}} \\ \\ y=\frac{\sqrt[]{x+12}}{3} \end{gathered}[/tex]so the option is D