Question

can someone please help me find the answer to this problem?

Answer 1

PART A

Line BA=22 and Line CD=14

Then MN

$\begin{gathered} \frac{22+14}{2}=\frac{36}{2} \\ MN=18\text{ } \\ X=18 \end{gathered}$

PART B

AD=BC

MC=ND=8

MN is the midsegment

AD IS 2 times 8=16

PART C

angle ABC= angle BAD ( Isosceles trapezoid)

[tex]\begin{gathered} M<\text{ABC}+M