KStrontium-90 decays according to the exponential function y = yowhere t is time in years. Match the given question with the correct procedure to answer the question.If the initial amount of Strontium-90 is 300 g, how much will remain after 18 yr?Choose the correct answer below.1OA. Solve Yo-Yo-0.02411-0.0241(30)-0.02411OB. Evaluate y=300 eO.C. Solve 0.75%-YoOD. Evaluate y = 300 -0.0241(18)-0.02411

KStrontium90 decays according to the exponential function y yowhere t is time in years Match the given question with the correct procedure to answer the questio class=

Respuesta :

Given:

[tex]y=y_0e^{-0.0241t}[/tex]

Where t is the time in years.

Initial amount = 300 g

Time, t = 18 years

Let's find the amount that will remain after 18 years.

Given that the function is an exponential decay function, we have:

Initial amount = y0

Final amount = y

time = t

To find the amount that will remain after 18 years, plug in 300 for y0 and 18 for t.

We have:

[tex]y=300e^{-0.0241(18)}[/tex]

Therefore, to find the amount remaining after 18 years, we are to evaluate the function below;

[tex]\begin{gathered} y=300e^{-0.0241(18)} \\ \\ y=194.4\text{ } \end{gathered}[/tex]

ANSWER: D

[tex]y=300e^{-0.0241(18)}[/tex]

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