Question

In AEFG, e = 6.9 inches, f = 8.7 inches and /G=27°. Find the length of g, to thenearest 10th of an inch.

Answer 1

We will determine the length of g as follows:

*First: We will use the law of cosines to solve, that is:

$g^2=(8.7)^2+(6.9)^2-2(8.7)(6.9)\cos (27)$

*Second: We solve:

$g=4.040514411\ldots\Rightarrow g\approx4.0$

So, the measure of the side g is approximately 4.0 inches long.