Question

3a raised to 7, b raised 6 / 18a raised to 6 , b raised to 8

Answer 1

Solution:

$\frac{3a^7b^6}{18a^6b^8}$$\begin{gathered} \frac{3a^{7}b^{6}}{18a^{6}b^{8}}\text{ = }\frac{3}{18}\text{ .}\frac{a^7}{a^6}.\frac{b^6}{b^8} \\ Appying\text{ the law of indices, } \\ \text{ }\frac{3}{18}\text{ .}\frac{a^7}{a^6}.\frac{b^6}{b^8}\text{ = }\frac{1}{6}a^{7-6}b^{6-8} \\ \\ =\frac{a^1b^{-2}}{6} \\ =\frac{a}{6b^2} \\ \\ The\text{ answer is }\frac{a}{6b^2} \end{gathered}$