irrational
Explanation
[tex]2\sqrt{7}-3\sqrt{7}[/tex]
Step 1
simplify
[tex]\begin{gathered} 2\sqrt{7}-3\sqrt{7} \\ 2\sqrt{7}-3\sqrt{7}=\left(2-3\right)\sqrt{7} \\ 2\sqrt{7}-3\sqrt{7}=(-)\sqrt{7} \\ 2\sqrt{7}-3\sqrt{7}=-\sqrt{7} \end{gathered}[/tex]Step 2
A rational expression is the ratio of two polynomials. If f is a rational expression then f can be written in the form a/b where a and b are polynomials
[tex]\begin{gathered} 2\sqrt{7}-3\sqrt{7}=-\sqrt{7} \\ -\sqrt{7}=-2.64575131106 \end{gathered}[/tex]It is an irrational number because evaluating √7 gives a non recurring, non terminating decimal number
it is impossible to find a value for –√7 which can be represented as a/b where a & b are integers.
so, the answer is
irrational
I hope this helps you