Respuesta :

irrational

Explanation

[tex]2\sqrt{7}-3\sqrt{7}[/tex]

Step 1

simplify

[tex]\begin{gathered} 2\sqrt{7}-3\sqrt{7} \\ 2\sqrt{7}-3\sqrt{7}=\left(2-3\right)\sqrt{7} \\ 2\sqrt{7}-3\sqrt{7}=(-)\sqrt{7} \\ 2\sqrt{7}-3\sqrt{7}=-\sqrt{7} \end{gathered}[/tex]

Step 2

A rational expression is the ratio of two polynomials. If f is a rational expression then f can be written in the form a/b where a and b are polynomials

[tex]\begin{gathered} 2\sqrt{7}-3\sqrt{7}=-\sqrt{7} \\ -\sqrt{7}=-2.64575131106 \end{gathered}[/tex]

It is an irrational number because evaluating √7 gives a non recurring, non terminating decimal number

it is impossible to find a value for –√7 which can be represented as a/b where a & b are integers.

so, the answer is

irrational

I hope this helps you

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