The functions are given to be:
[tex]\begin{gathered} f(x)=2x^2-1 \\ g(x)=-3x+2 \end{gathered}[/tex]To evaluate g(f(1)), we will first find f(1):
[tex]\begin{gathered} f(1)=2(1)^2-1 \\ f(1)=2-1 \\ f(1)=1 \end{gathered}[/tex]Next, we evaluate g(1):
[tex]\begin{gathered} g(1)=-3(1)+2 \\ g(1)=-3+2 \\ g(1)=-1 \end{gathered}[/tex]Therefore, the answer is:
[tex]g(f(1))=-1[/tex]