step 1
Find out the volume of the piece of steel
The volume of the figure is equal to the volume of a cylinder plus the volume of a cone
so
[tex]V=\pi\cdot r^2\cdot h+\frac{1}{3}\cdot\pi^{}\cdot r^2\cdot h[/tex]
we have
h cylinder=4.5 in
r=2.28/2=1.14 in
hcone=1.5 in
substitute given values in the formula
[tex]V=\pi\cdot1.14^2\cdot4.5+\frac{1}{3}\cdot\pi^{}\cdot1.14^2\cdot1.5[/tex]
V=20.4 in3
step 2
Multiply the density by the volume
0.283*20.4=5.8 lb
therefore
the answer is 5.8 lb
