ANSWER
[tex]\begin{gathered} 8.3129years \\ \end{gathered}[/tex]EXPLANATION
Given;
Initial Quantity (Ao) = 1000
Rate (r) is 8
The Final Quantity (A(t)) = 500
[tex]r=8=-\frac{8}{100}=-0.08[/tex]Using the rate formula;
[tex]\begin{gathered} A\left(t\right)=A_0(1+r)^t \\ \end{gathered}[/tex]Substituting the values;
[tex]\begin{gathered} A(t)=A_{0}(1+r)^{t} \\ 500=1000(1-0.08)^t \\ 500=1000(0.92)^t \\ \frac{500}{1000}=0.92^t \\ 0.5=0.92^t \end{gathered}[/tex]Using logarithm to solve for t;
[tex]\begin{gathered} t=\frac{log0.5}{log0.92} \\ =\frac{-0.3010}{-0.036} \\ =8.3129 \\ \approx8.31(2d.p) \end{gathered}[/tex]Exact answer is 8.31295.