Question

Typically, water runs through the baseboard copper tubing and therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water wasallowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change of the water if 198.0 g of water sat in the copper pipe from partA releasing 3072 J of energy to the pipe? The specific heat of water is 4.184 J/(g• °C)Express your answer to four significant figures.

Answer 1

Explanation:

We have to find the temperature change of a 198.0 g sample of hot water that released 3072 J to a pipe. So we know that:

Q = -3072 J (negative because the water is releasing the heat)

m = 198.0 g

Cp = 4.184 J/(g°C)

The temperature change is our unknown, so we can apply this formula and solve it for ΔT:

Q = m * Cp * ΔT

ΔT = Q/(m * Cp)

ΔT = -3072 J/(198.0 g * 4.184 J/(g°C))

ΔT = - 3.708 °C

Answer: The temperature change of the water will be -3.708 °C