graph a right triangle with two points forming the hypotenuse. using the sides, find the distance between the two points, to the nearest tenth if possible (6,-5) and (-3, 3)

We will have the following:
*First. We determine a new point that can be used to complete the rigth triangle; we are given the points:
[tex]\begin{cases}(6,-5) \\ \\ (-3,3)\end{cases}[/tex]So, a point we could use to form a rigth triangle could be:
[tex](-3,-5)[/tex]And we would have the following triangle:
*Second: We determine the distances:
**Distance on the horizontal axis would be 9 units.
**Distance on the vertical axis would be 8 units.
*Third: We determine the distance betweem the two original points:
[tex]h=\sqrt[]{9^2+8^2}\Rightarrow h=\sqrt[]{145}[/tex][tex]\Rightarrow h=12.04159458\ldots\Rightarrow h\approx12[/tex]So, the distance between the two original points is approximately 12 units.