Notice that 13 and 5 are prime numbers; therefore, the minimum common divisor is 13*5=65. Thus, we can calculate that addition as shown below.
[tex]\begin{gathered} -\frac{7}{13}\cdot\frac{5}{5}+\frac{6}{5}\cdot\frac{13}{13}=-\frac{35}{65}+\frac{78}{65} \\ =\frac{43}{65} \end{gathered}[/tex]The answer is 43/65.
2)
[tex]\frac{3}{11}+(-\frac{5}{12})[/tex]Solve as shown below
[tex]\begin{gathered} \frac{3}{11}+(-\frac{5}{12}) \\ =\frac{3}{11}\cdot\frac{12}{12}+(-\frac{5}{12})\cdot\frac{11}{11} \\ =\frac{36}{132}+(-\frac{55}{132}) \\ =\frac{36-55}{132} \\ =\frac{-19}{132} \end{gathered}[/tex]The answer is -19/132
