Multiply the first equation by 4:
[tex]\begin{gathered} 4(2x+3y=9) \\ 8x+12y=36 \end{gathered}[/tex]Subtract the second equation:
[tex]\begin{gathered} 8x+12y=36 \\ - \\ 8x-5y=19 \end{gathered}[/tex]This is:
[tex]\begin{gathered} 8x+12y-(8x-5y)=36-19 \\ 8x+12y-8x+5y=17 \end{gathered}[/tex]Simplify:
[tex]\begin{gathered} 17y=17 \\ \frac{17y}{17}=\frac{17}{17} \\ y=1 \end{gathered}[/tex]Substitute y = 1 in the first equation:
[tex]\begin{gathered} 2x+3(1)=9 \\ 2x+3=9 \end{gathered}[/tex]Ans solve for x:
[tex]\begin{gathered} 2x+3-3=9-3 \\ 2x=6 \\ \frac{2x}{2}=\frac{6}{2} \\ x=3 \end{gathered}[/tex]Answer:
x = 3
y = 1