Answer:
x = -2
y = 3
Explanation:
We are given that:
[tex]\begin{gathered} 4x-2y=-14-----1 \\ -x+2y=8------2 \end{gathered}[/tex]
We will proceed to solve this system of equations as shown below:
[tex]\begin{gathered} 4x-2y=-14-----1 \\ -x+2y=8------2 \\ \text{We will proceed to sum both equations 1 \& 2, we have:} \\ 4x-x=-14+8 \\ 3x=-6 \\ \text{Divide both sides by ''3'', we have:} \\ x=-\frac{6}{3} \\ x=-2 \\ \text{Substitute the value of ''x'' into equation 2, we have:} \\ -(-2)+2y=8 \\ 2+2y=8 \\ \text{Subtract ''2'' from both sides, we have:} \\ 2y=8-2 \\ 2y=6 \\ \text{Divide both sides by ''2'', we have:} \\ y=\frac{6}{2} \\ y=3 \\ \\ \therefore x=-2,y=3 \end{gathered}[/tex]
x = -2, y = 3
