Question

Car X leaves Northtown traveling at a steady rate of 55 mph. Car Y leaves 1 hour later following Car X, traveling at a steady rate of 60 mph. Which equation can be used to determine how long after Car X leaves Car Y will catch up? A. 55x=60x-1 B.55x=60x C.60x=55x(x-1) D.55x=60(x-1)

Answer 1

If x is the time that Car X takes, then the time of Car Y will be (x - 1)

Car X will travel a distance = 55 (x) = 55x miles

Care Y will travel a distance = 60 (x - 1)

Then Both will meet each other at

55 x = 60 (x - 1)

The answer is D