Question

4(u+3)-6u=32solve for u.

Answer 1

Answer:

The solution to the equation is;

$u=-10$

Explanation:

Given the equation;

$4(u+3)-6u=32$

let us expand and solve;

$\begin{gathered} 4u+12-6u=32 \\ 4u-6u+12=32 \\ -2u+12=32 \\ -2u=32-12 \\ -2u=20\text{ ------divide both sides by -2} \\ u=\frac{20}{-2} \\ u=-10 \end{gathered}$

Therefore, the solution to the equation is;

$u=-10$