Question

Jennifer and Michael walk with an average velocity of 0.89 m/s eastward if it takes them 43 minutes to walk to the store what is their displacement

Answer 1

ANSWER

2296.2 m

EXPLANATION

The average velocity is the quotient between the displacement and time:

$v_{avg}=\frac{\Delta x}{\Delta t}$

Solving for displacement:

$\Delta x=v_{\text{avg}}\cdot\Delta t$

We know that they walk at an average velocity of 0.89 m/s and it took them 43 minutes to get to the store. First we have to either convert the time from minutes to seconds or convert the velocity from m/s to m per minute. Let's convert the time, because it is a bit faster:

$\begin{gathered} 1\min =60s \\ t=43\min =43\min \cdot\frac{60s}{1\min }=2580s \end{gathered}$

Now we can multiply the velocity and time, because their units are consistent:

$\Delta x=0.89\frac{m}{s}\cdot2580s=2296.2m$

Their displacement to the store was 2296.2 meters