Question

consider these functions: f(x)= 1/3x^2 +4g(x)=9x-12 what is the value of g(f(x))

Answer 1

Answer

Explanation

Given:

$\begin{gathered} f(x)=\frac{1}{3}x^2+4 \\ g(x)=9x-12 \end{gathered}$

To determine the value of g(f(x)), we substitute x with 1/3x^2+4 for g=9x-12:

$\begin{gathered} g(x)=9x-12 \\ g(\frac{1}{3}x^2+4)=9(\frac{1}{3}x^2+4)-12 \\ Simplify \\ =3x^2+36-12 \\ =3x^2+24 \end{gathered}$

Therefore, the value of g(f(x)) is C:

$\begin{equation*} 3x^2+24 \end{equation*}$