Question

An iron casting is made in a mold with a hot length of 16.30 in. After cooling, the casting is 16.05 in. long. What is the shrinkage in percent?

Answer 1

First, subtract the hot length by the cooled length.

$16.30\text{ in}-16.05\text{ in}=0.25\text{ in}$

Next, divide the difference from the hot length, and multiply by 100% to get the percentage.

$\begin{gathered} 0.25\text{ in}\div16.30\text{ in}=0.0153374 \\ 0.0153374\times100\%=1.53374\% \end{gathered}$

Rounding to the nearest the nearest one decimal place, the shrinkage in percent is 1.5%.