Let the given number be 'x',
[tex]\begin{gathered} x=0.4\bar{5} \\ x=0.45555555\ldots\ldots \end{gathered}[/tex]Multiply both sides by 10,
[tex]\begin{gathered} 10x=4.\bar{5} \\ 10x=4.5555555\ldots\ldots \end{gathered}[/tex]Subtract the equations,
[tex]\begin{gathered} 10x-x=4.5555\ldots-0.45555\ldots \\ 9x=4.5+0.0\bar{5}-(0.4+0.0\bar{5}) \\ 9x=4.5+0.0\bar{5}-0.4-0.0\bar{5} \\ 9x=4.1 \\ 9x=\frac{41}{10} \\ x=\frac{41}{90} \end{gathered}[/tex]Thus, the recurring decimal number is equivalent to the fraction,
[tex]0.4\bar{5}=\frac{41}{90}[/tex]