The length of NO is 80.
Given:
The length of the side ML is 2x+50.
The length of the side NO is 4x+20.
The objective is to find the length of NO.
Since the given figure resembles the shape of a rhombus, the opposite sides are equal.
Then, the value of x can be calculated as,
[tex]\begin{gathered} ML=NO \\ 2x+50=4x+20 \\ 2x-4x=20-50 \\ -2x=-30 \\ x=-\frac{30}{-2} \\ x=15 \end{gathered}[/tex]
Now substitute the value of x in the equation of NO.
[tex]\begin{gathered} NO=4x+20 \\ =4(15)+20 \\ =60+20 \\ =80 \end{gathered}[/tex]
Hence, the length of NO is 80.
