Question

The height of an object tossed upward with an initial velocity of 152 feet per second is given by the formula h = −16t2 + 152t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure.

Answer 1

We will determine the time required for the object to return to its point of departure as follows:

$\begin{gathered} -16t^2+152t=0\Rightarrow t=\frac{-(152)\pm\sqrt{(152)^2-4(-16)(0)}}{2(-16)} \\ \\ \Rightarrow t=9.5 \end{gathered}$

So, it will take 9.5 seconds to return to its original position.