Question

Esmeralda cut out two paper rectangles and glued them together as shown in the figure.Find the area of the Esmeralda's composite figure.A)32 cmB)40 cmC)48 cmD)56 cm

Answer 1

The given figure can be redrawn as,

The area of a rectangle is the product of length and breadth of the rectangle.

Hence, the area of rectangle ABCD is,

$\begin{gathered} \text{Area}_{ABCD}=AB\times AD \\ =2\times6 \\ =12cm^2 \end{gathered}$

The area of rectangle ECGF is,

$\begin{gathered} \text{Area}_{ECGF}=EF\times FG \\ =4\times7 \\ =28cm^2 \end{gathered}$

Hence, the total area of the figure is,

$\begin{gathered} \text{Area}=Area_{\text{ABCD}}+Area_{ECGF} \\ =12+28 \\ =40cm^2 \end{gathered}$

Therefore, the area of the figure is 40 cm^2.

Hence, option (B) is correct