Question

7:40 PM Tue Mardoltamathcom - PeluateThe segment below is dilated by a scale factor of to form J'K'. What is themeasure of J'K'?24

Answer 1

Since J'K' is a dilation of JK, we have that

$J^{\prime}K^{\prime}=c\cdot JK$

Where c is the scale factor of the dilation; therefore,

$\begin{gathered} \Rightarrow J^{\prime}K^{\prime}=\frac{1}{3}\cdot JK=\frac{1}{3}\cdot24=8 \\ \Rightarrow J^{\prime}K^{\prime}=8 \end{gathered}$

The answer is J'K'=8