A square based pyramid comprises of four(4) tirangular faces and a square base.
Area of a square =L², where Length of the square (L)=10m
Area of the triangle
[tex]\frac{1}{2}\times base\text{ }\times height[/tex]The height of the triangular faces is representented the slant height of the pyramid
Then the height of the triangle (h)=13m and base =10m
The total surface area of a square based pyramid is given as
[tex]\text{area of the square base + area of the 4 triangular faces}[/tex][tex]\begin{gathered} \text{Area of square=L}^2 \\ \text{Area of square= 10}^2 \\ Areaofsquare=100m^2 \end{gathered}[/tex]Area of 4 triangular faces
[tex]4\times\frac{1}{2}\times base\times height[/tex][tex]\begin{gathered} 4\times\frac{1}{2}\times10\times13 \\ A\text{rea of 4 triangular faces=260m}^2 \end{gathered}[/tex]Therefore the total surface area of the square based pyramid is
[tex]100m^{2\text{ }}+260m^2=360m^2[/tex]Hence from the question the correct option would be option B=360m²