Question

A worker pushes horizontally on a large crate with a force of 165 N, and the crate is moved 3.5 m. How much work was done? answer in joule

Answer 1

Given data:

* The force acting on the crate in the horizontal direction is 165 N.

* The displacement of the crate is 3.5 m.

Soluiton:

The work done by the worker is,

$W=Fd\cos (\theta)$

where W is the work done, F is the applied force, d is the displacement,

$\text{and }\theta\text{ is the angle between force and displacement,}$

As, both the force and displacement is in the horizontal direction.

Thus,

$\theta=0^{\circ}$

Substituting the known values in the work equation,

$\begin{gathered} W=165\times3.5\times\cos (0^{\circ}) \\ W=577.5\text{ J} \end{gathered}$

Thus, the work done by the worker on the crate is 577.5 joule.