Question

Solve the equation. d2 + 5 = 41 р and d= 1

Answer 1

ANSWERS

• d = 6

,

• d = -6

EXPLANATION

To solve this equation first we have to substract 5 from both sides of the equation:

$\begin{gathered} d^2+5-5=41-5 \\ d^2=36 \end{gathered}$

Now we have to apply the square root on both sides of the equation. Remember that the square root has 2 results: one positive and one negative. But if you apply the square root to a square power, you have the absolute value:

$\begin{gathered} \sqrt[]{d^2}=\pm\sqrt[]{36} \\ d=\pm6 \end{gathered}$

Therefore the solutions of this equation are d = 6 and d = -6