The youth hockey team already played 3 matches in which they scored 6, 9 and 2 goals.
Let
the score of the fourth goal = x
[tex]\begin{gathered} \frac{6+9+2+x}{4}>5 \\ \frac{17+x}{4}>5 \\ \text{multiply both sides by 4} \\ (\frac{17+x}{4})4>5\times4 \\ 17+x>20 \\ \text{subtract 17 from both sides} \\ 17-17+x>20-17 \\ x>3 \end{gathered}[/tex]The number of goals must be greater than 3 for the average score to be greater than 5
