Question

10 g of water. specific heat of water is 4.18 J/g°C. temperature changes from 35° C to30° C, how much heat energy (Q) moves from the water to the surroundings?

Answer 1

ANSWER:

-209 J

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 10 g

Specific heat (s) = 4.18 J/g*°C

Temperature change (ΔT) = 30°C - 35°C = -5°C

The heat energy is calculated by the following formula:

$\begin{gathered} Q=m\cdot s\cdot\Delta T \\ \\ \text{ We replacing:} \\ \\ Q=10\cdot4.18\cdot-5 \\ \\ Q=-209\text{ J} \end{gathered}$

It means that the heat energy that is transferred is 209 J