Question

can you help me with this. I need equation and angle

Answer 1

The equation for a simple harmonic motion (SHM) is given by:

$y=A\cdot\sin (wt+\alpha)$

Where A is the amplitude, alpha is the initial phase and the period is given by T = 2π/omega.

So, for A = 2, T = 1.5 and alpha1 = π/2. we have:

$\begin{gathered} \omega=\frac{2\pi}{T}=\frac{2\pi}{1.5}=\frac{4\pi}{3} \\ \\ y_1=2\cdot\sin (\frac{4\pi}{3}t+\frac{\pi}{2}) \end{gathered}$

For A = 2, T = 1.5 and alpha = π/3, we have:

$y_2=2\sin (\frac{4\pi}{3}t+\frac{\pi}{3})$

Now, adding both oscillations, we have:

$\begin{gathered} y=y_1+y_2 \\ y=2(\sin (\frac{4\pi}{3}t+\frac{\pi}{2})+\sin (\frac{4\pi}{3}t+\frac{\pi}{3})) \end{gathered}$