Solution:
Given:
[tex]\begin{gathered} \operatorname{Re}d=3\text{balls} \\ \text{Green}=4\text{balls} \\ \text{Yellow}=3\text{balls} \\ TOTAL=10balls \end{gathered}[/tex]To get the probability that a ball picked is red, we use the formula for probability below,
[tex]\text{Probability}=\frac{n\text{ umber of required outcome}}{n\text{ umber of total or possible outcomes}}[/tex]Hence,
[tex]\begin{gathered} \text{Probability}=\frac{n\text{ umber of required outcome}}{n\text{ umber of total or possible outcomes}} \\ \text{Probability}=\frac{n\text{ umber of red balls}}{\text{ total number of balls}} \\ \text{Probability}=\frac{3}{10} \end{gathered}[/tex]Therefore, the probability that the ball is red is;
[tex]\frac{3}{10}[/tex]Hence, the correct answer is OPTION B.