Show WhatGiven the fact that MN is the midsegment of triangle ABC, use the diagram below to write the equation for finding x.9x-44M MB2x+3NсEquation for finding x341 2

Show WhatGiven the fact that MN is the midsegment of triangle ABC use the diagram below to write the equation for finding x9x44M MB2x3NсEquation for finding x34 class=

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Since MN is the midsegment, then the proportion of the side is equal to 1/2. Thus the equation for finding x is the following equation.

[tex]\frac{2x+3}{9x-44}=\frac{1}{2}[/tex]

Thus, to solve for the value of x, multiply both sides of the equation by 2(9x-44). This will eliminate the denominators.

[tex]2(2x+3)=9x-44[/tex]

Simplify both sides of the equation.

[tex]4x+6=9x-44[/tex]

Isolate the variables on one side of the equation by subtracting 4x and adding 44 to both sides of the equation.

[tex]\begin{gathered} 6+44=9x-4x \\ 50=5x \end{gathered}[/tex]

To obtain the value of x, divide both sides of the equation by 5.

[tex]\begin{gathered} \frac{50}{5}=\frac{5x}{5} \\ 10=x \end{gathered}[/tex]

Thus, the value of x is 10.

To solve for MN, substitute the value of x, which is 10, into the expression 2x+3 and then simplify.

[tex]\begin{gathered} MN=2(10)+3 \\ MN=20+3 \\ MN=23 \end{gathered}[/tex]

To solve for AB, substitute the value of x, which is 10, into the expression 9x-44 and then simplify.

[tex]\begin{gathered} AB=9(10)-44 \\ AB=90-44 \\ AB=46 \end{gathered}[/tex]

Notice that AB is twice the measure of MN.

Therefore the answers in the blanks should be:

Equation: 2(2x+3)=9x-44

[tex]\begin{gathered} x=10 \\ MN=23 \\ AB=46 \end{gathered}[/tex]

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