Find the Surface area of a pentagonal prism with a base area of 110in^2Formula: SA= p * h + 2 * b

p represent the perimeter of the base, assuming that the pentagon is regular we get:
[tex]p=8\cdot5=40\text{ in}[/tex]h represents the hight of the prism, which in this case is:
[tex]h=20\text{ in}[/tex]B represents the base area, which in this case is:
[tex]B=110in^2[/tex]The surface area is:
[tex]\text{SufaceArea}=40in\cdot20in+2\cdot110in^2[/tex][tex]\text{SufaceArea}=800in^2+220in^2[/tex][tex]\text{SufaceArea}=1020in^2[/tex]