Question

What is the energy of a photon (J) that has a frequency of 4.39 × 10^19 Hz?A) 2.91 × 10-14B) 2.91 × 1020C) 6.83 × 10-12 D) 2.91 × 10-52E) 2.91 × 1054

Answer 1

Answer

2.91 × 10⁻¹⁴ J

Procedure

The energy of a photon can be calculated using the following equation:

$E=hf$

Where:

E is energy (J)

h is Planck's constant: 6.62607015 × 10⁻³⁴ (m²kgs⁻¹)

f is the frequency (Hz)

Given our data, the equation will be

$E=6.62607015\times10^{-34}\frac{m^2kg}{s}\times(4.39\times10^{19}Hz)=2.91\times10^{-14}J$