Given:
[tex]3+\frac{2}{5}b=11-\frac{2}{5}b[/tex]Required:
To find the value of b.
Explanation:
Consider
[tex]\begin{gathered} 3+\frac{2}{5}b=11-\frac{2}{5}b \\ \\ \frac{2}{5}b+\frac{2}{5}b=11-3 \\ \\ b(\frac{2}{5}+\frac{2}{5})=8_ \\ \\ \\ b(\frac{4}{5})=8 \\ \\ b=8\times\frac{5}{4} \\ \\ b=10 \end{gathered}[/tex]Final Answer:
[tex]b=10[/tex]