The volume of a cone with height h=5 is given by,
[tex]V=\frac{5}{3}\pi r^2[/tex]The volume of the above type of cone is given to be V=2π.
So, substitute V=2π in above equation and solve for r.
[tex]\begin{gathered} 2\pi=\frac{5}{3}\pi r^2 \\ \frac{2\cdot3}{5}=r^2 \\ \frac{6}{5}=r^2 \\ r=\sqrt[]{\frac{6}{5}} \\ r=1.095 \end{gathered}[/tex]Therefore, the radius of the cone is 1.095.