Question

Find the slope of the line determined by the equation 3x + 10y = 11 O A. m= -3 Bm=3 O C. m=- 10 DI 11 10 DE m = -10

Answer 1

$\begin{gathered} 3x+10y=11 \\ 10y=-3x+11 \\ y=-\frac{3}{10}+\frac{11}{10} \\ slope,\text{ m=}\frac{-3}{10} \end{gathered}$