Question

Need help with chemistry #4The specific heat of metal is 0.222 cal/g°C. If 587.0 calories of heat energy are added to a chunk of gold and the temperature rises from 18.9°C to 38.8°C, find the mass (in grams) of the piece of gold.

Answer 1

Answer

132.9 grams

Explanation

Given:

Specific heat of the gold metal, c = 0.222 cal/g°C

Quantity of heat energy, Q = 587.0 cal

Initial temperature, T₁ = 18.9 °C

Final temperature, T₂ = 38.8 °C

Temperature change, ΔT = T₂ - T₁ = 38.8 °C - 18.9 °C = 19.9 °C

What to find:

The mass (in grams) of the piece of gold.

Step-by-step solution:

The mass (in grams) of the piece of gold can be calculated using the formula below;

$\begin{gathered} Q=mc\Delta T \\ \\ \Rightarrow m=\frac{Q}{c\Delta T} \end{gathered}$

Putting the values of the parameters into the formula, we have

$m=\frac{587.0\text{ }cal}{0.222\text{ }cal\text{/}g°C\times19.9\text{ }°C}=\frac{587.0\text{ }g}{4.4178}=132.9\text{ }grams$

The mass (in grams) of the piece of gold is 132.9 grams.