Question

Welcome to Facebo... Quiz: 11.1-11.5 Quiz This Question: 1 pt 9 of 28 (7 complete) Math Second Roll A single die is rolled twice. The 36 equally-likely outcomes are shown to the right Find the probability of getting two numbers whose sum exceeds 12. First Roll (1.1) (1.2) (1.3) (1.4) (1.5) (1,6) (2.1) (2.2) (2.3) (2.4) (2.5) (2.6) |(3.1) (3,2) (3.3) (3.4) (3.5) (3,6) |(4.1) (4,2) (4.3) (4.4) (4.5) (4.6) (5.1) (5.2) (5.3) (5.4) (5.5) (5.6) (6,1) (6,2) (6,3) (6.4) (6,5) (6.6) The probability of getting two numbers whose sum exceeds 12 is (Type an integer or a simplified fraction.) ents cess Library cess >

Answer 1

If we see the possible outcomes, the greatest sum of the possible outcomes is 12 ( when we get a double six), so there is no possible outcome that the sum of the numbers exceeds 12. Then, the probability is

$\frac{0}{36}=0$