The perimeter of a circumference is 2πr, where r is the radius of the circumference. Thus, the perimeter of half a circumference is πr.
The semi-circumference part of the figure has a diameter of 5 ft. So, its radius, which is half the diameter, is 2.5 ft.
So, the length, in feet, of that part is
2.5π ≅ 2.5 * 3.14 ≅ 7.85
The length, in feet, of the bottom plus the top of the rectangular part is 8 + 8 = 16.
The bottom of the triangle measures, in feet, 3.
And the hypotenuse of the triangle (the left side of the figure), measures, in feet:
[tex]\sqrt{3² +5²}=\sqrt[]{9+25}=\sqrt[]{34}\cong5.83[/tex]
Then, adding all those parts, we find the perimeter, in feet, to be:
[tex]7.85+16+3+5.83=32.68\cong32.7[/tex]
Therefore, the perimeter of the figure, rounded to one decimal place, is:
32.7 ft
