The logarithmic form of an equation can be changed into exponential form via
[tex]y=\log _bx\rightarrow x=b^y[/tex]On the given logarithmic equation
[tex]\log _5\frac{1}{125}=-3[/tex]We have y = -3, x = 1/125, and b = 5. Based on the definition stated above, the logarithmic equation given can be rewritten in exponential form as
[tex]\frac{1}{125}=5^{-3}[/tex]Therefore, the answer is choice B.
