Question

Evaluate the exponential function h(x)-+8 for h(-5). Round to 4 decimal places, if necessary.3h(-5) =help (formulas)

Answer 1

Given:

$h(x)=\frac{1}{3}(\frac{1}{3})^x+8$

Find the value is h(-5)

Sol:

$h(x)=\frac{1}{3}(\frac{1}{3})^x+8$

h(-5) value at x = -5 so,

$\begin{gathered} h(x)=\frac{1}{3}(\frac{1}{3})^x+8 \\ \\ h(-5)=\frac{1}{3}(\frac{1}{3})^{-5}+8 \\ \\ h(-5)=(\frac{1}{3})^{-4}+8 \\ \\ h(-5)=81+8 \\ \\ h(-5)=89 \end{gathered}$

So, the value is 89.