Respuesta :

Given:

[tex]h(x)=\frac{1}{3}(\frac{1}{3})^x+8[/tex]

Find the value is h(-5)

Sol:

[tex]h(x)=\frac{1}{3}(\frac{1}{3})^x+8[/tex]

h(-5) value at x = -5 so,

[tex]\begin{gathered} h(x)=\frac{1}{3}(\frac{1}{3})^x+8 \\ \\ h(-5)=\frac{1}{3}(\frac{1}{3})^{-5}+8 \\ \\ h(-5)=(\frac{1}{3})^{-4}+8 \\ \\ h(-5)=81+8 \\ \\ h(-5)=89 \end{gathered}[/tex]

So, the value is 89.

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