Here we go........................
[tex]\begin{gathered} \text{Null Hypothesis = H}_0\text{ = }\mu\text{ = 5400} \\ \text{Alternative Hypothesis = H}_1\text{ = }\mu\text{ < }5400\text{ and this is the CLAIM} \\ \text{Degre}e\text{ of fr}eedom\text{ = df = 27} \\ \text{critical value CV = -2.052} \end{gathered}[/tex]finding the test value.....
[tex]t-\text{value = }\frac{5250\text{ - 5400}}{\frac{629}{\sqrt[]{28}}}\text{ = }-1.262[/tex]